A) \[2.35\times {{10}^{17}}g/c{{m}^{-3}}\]
B) \[2.35\times {{10}^{17}}kg/c{{m}^{-3}}\]
C) \[2.35\times {{10}^{17}}c{{m}^{-3}}\]
D) \[2.35\times {{10}^{17}}kg\,\,m{{m}^{-3}}\]
Correct Answer: B
Solution :
[b] For nucleus of \[_{8}{{O}^{16}}\] Mass \[=(16)\,(1.67\times {{10}^{-27}})kg\] Volume \[=\frac{4}{3}\pi {{R}^{3}}\] \[=\frac{4}{3}\pi {{(3\times {{10}^{-15}})}^{3}}{{m}^{3}}=36\pi \times {{10}^{-45}}{{m}^{3}}\] Density \[=\frac{mass}{volume}=\frac{16\times 1.67\times {{10}^{-27}}kg}{36\pi \times {{10}^{-45}}{{m}^{3}}}\] \[=2.35\times {{10}^{17}}kg{{m}^{-3}}\]
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