question_answer

A wire carrying current I is tied between points P and Q and is in the shape of a circular arc of radius R due to a uniform magnetic field B    (perpendicular to the plane of the paper, shown by xxx) in the vicinity of the wire. If the wire subtends an angle \[2{{\theta }_{0}}\] at the centre of the circle (of which it forms an arc) then the tension in the wire is:

A) \[\frac{IBR}{2\,\sin \,{{\theta }_{0}}}\]

B) \[\frac{IBR{{\theta }_{0}}}{\sin \,{{\theta }_{0}}}\]

C) \[IBR\]

D) \[\frac{IBR}{\sin {{\theta }_{0}}}\]