A) \[40\,\pi \,rad\,{{s}^{-2}}\]
B) \[20\,\pi \,rad\,{{s}^{-2}}\]
C) \[5\,\pi \,rad\,{{s}^{-2}}\]
D) \[15\,\pi \,rad\,{{s}^{-2}}\]
Correct Answer: A
Solution :
[a] Due to torque of magnetic field, ring will rotate about vertical diameter. \[\tau =I\alpha \Rightarrow MB=I\alpha \] \[\Rightarrow \,\,\,\,i\pi {{r}^{2}}B=\frac{1}{2}m{{r}^{2}}\alpha \] \[\Rightarrow \,\,\,\,\alpha =\frac{2iB\pi }{m}=\frac{2\times 4\times 10\pi }{2}=40\pi \,rad\,{{s}^{-2}}\]
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