A) \[1.6\times {{10}^{-19}}A{{m}^{2}}\]
B) \[5.3\times {{10}^{-21}}A{{m}^{2}}\]
C) \[8.8\times {{10}^{-26}}A{{m}^{2}}\]
D) \[8.8\times {{10}^{-25}}A{{m}^{2}}\]
Correct Answer: C
Solution :
[c] Magnetic dipole moment \[m=iA=\frac{e}{T}\times \pi {{r}^{2}}=\frac{e}{(2\pi r/v)}\times \pi {{r}^{2}}=\frac{erv}{2}.\] \[=\frac{1.6\times {{10}^{-19}}\times 50\times {{10}^{-12}}\times 2.2\times {{10}^{6}}}{2}\] \[=8.8\times {{10}^{-25}}\,A{{m}^{2}}\].
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