A) 0.14N
B) 0.24 N
C) 0.34 N
D) 0.44N
Correct Answer: B
Solution :
[b] \[F=IIB\] Here, \[\theta ={{90}^{o}}\], \[I=10A\] \[I=8\,cm=8\times {{10}^{-2}}m\], \[B=0.3\,T\] \[\therefore \,\,\,\,F=10\times 8\times {{10}^{-2}}\times 0.3\times \sin \,{{90}^{o}}=0.24\,N\]
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