A) 9.5
B) 7.2
C) 5.0
D) 3.2
Correct Answer: D
Solution :
[d] Given: \[f=24\times {{10}^{6}}Hz,\,\,\,\,R=0.60m\] We know that, \[R=\frac{mv}{qB}\] \[\therefore \,\,\,B=\frac{mv}{qR}\] ?..(i) where \[v=\omega R=2\pi fR\] \[=2\pi \times 24\times {{10}^{6}}\times 0.60=9.04\times {{10}^{7}}m/s\] From (i), \[B=\frac{(3.34\times {{10}^{-27}})(9.04\times {{10}^{7}})}{1.6\times {{10}^{-19}}\times 0.60}=3.2T\],
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