A) \[\frac{1}{2}m{{s}^{-2}}\] toward north
B) \[\frac{1}{\sqrt{2}}m{{s}^{-2}}\] toward north-east
C) \[\frac{1}{\sqrt{2}}m{{s}^{-2}}\] towards north-west
D) zero
Correct Answer: C
Solution :
\[\text{Average acceleration =}\frac{\text{change in velocity}}{\text{time interval}}\]You need to login to perform this action.
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