A) \[\frac{\pi {{\text{v}}^{2}}}{\text{g}}\]
B) \[\frac{\pi {{\text{v}}^{4}}}{{{\text{g}}^{2}}}\]
C) \[{{\pi }^{2}}\frac{{{\text{v}}^{2}}}{{{\text{g}}^{2}}}\]
D) \[\frac{{{\pi }^{2}}{{\text{v}}^{4}}}{{{\text{g}}^{2}}}\]
Correct Answer: B
Solution :
[b] Maximum possible horizontal range Maximum possible area of the circle \[=\pi {{\left( \frac{{{\text{v}}^{\text{2}}}}{\text{g}} \right)}^{2}}=\frac{\pi \,{{\text{v}}^{4}}}{{{\text{g}}^{2}}}\left[ \text{Here r=}\frac{{{\text{v}}^{\text{2}}}}{\text{g}} \right]\]
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