JEE Main & Advanced Physics Two Dimensional Motion Question Bank Self Evaluation Test - Motion in a Plane

  • question_answer
    A particle is projected at angle \[37{}^\circ \] with the incline plane in upward direction with speed 10 m/s. The angle of incline plane is given \[53{}^\circ \]. Then the maximum height attained by the particle from the incline plane will be

    A) 3 m      

    B)        4 m  

    C) 5 m      

    D)        zero

    Correct Answer: A

    Solution :

    [a] \[H=\frac{{{u}_{\bot }}^{2}}{2{{g}_{\bot }}}\Rightarrow H=\frac{10\sin 37{}^\circ \times 10\sin 37{}^\circ }{2\times g\cos 53{}^\circ }=3m\]


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