JEE Main & Advanced Physics Two Dimensional Motion Question Bank Self Evaluation Test - Motion in a Plane

  • question_answer
    A particle is projected at an angle of elevation \[\alpha \] and after t seconds it appears to have an angle of elevation \[\beta \] as seen from point of projection. The initial velocity will be

    A) \[\frac{gt}{2\sin \left( \alpha -\beta  \right)}\]

    B)        \[\frac{gt\,\cos \beta }{2\sin \left( \alpha -\beta  \right)}\]

    C) \[\frac{\sin \left( \alpha -\beta  \right)}{2gt}\]         

    D)        \[\frac{2\sin \left( \alpha -\beta  \right)}{gt\,\cos \beta }\]

    Correct Answer: B

    Solution :

    [b] \[t=\frac{2u\sin \left( \alpha -\beta  \right)}{g\cos \beta }.\text{  };\text{ }u=\frac{gt\cos \beta }{2\sin \left( \alpha -\beta  \right)}\]


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