JEE Main & Advanced Physics Two Dimensional Motion Question Bank Self Evaluation Test - Motion in a Plane

  • question_answer
    A projectile is given an initial velocity of \[\left( \hat{i}\text{ }+\text{ }2\text{ }\hat{j} \right)\text{ }m/s\], where; is along the ground and j is along the vertical. If \[g=10\text{ }m/{{s}^{2}}\], the equation of its trajectory is :

    A) \[y=x-5{{x}^{2}}\]     

    B)        \[y=2x-5{{x}^{2}}\]

    C) \[4y=2x-5{{x}^{2~}}~\]

    D)        \[4y=2x-25{{x}^{2}}\]

    Correct Answer: B

    Solution :

    [b] From equation, \[\vec{v}=\hat{i}+2\hat{j}\]          \[\Rightarrow x=t\]                                  ...(i) \[y=2t-\frac{1}{2}\left( 10{{t}^{2}} \right)\]                    ...(ii) From (i) and (ii), \[y=2x-5{{x}^{2}}\]


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