2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Two Dimensional Motion

JEE Main & Advanced Physics Two Dimensional Motion Question Bank Self Evaluation Test - Motion in a Plane

  • question_answer
    The equation of a projectile is \[y=\sqrt{3}x-\frac{\text{g}{{\text{x}}^{2}}}{20}\] The angle of projection is given by

    A) \[\text{tan}\theta \,\text{=}\frac{1}{\sqrt{3}}\]    

    B)        \[\text{tan}\theta \,\text{=}\,\sqrt{3}\]

    C)  \[\frac{\pi }{2}\]                

    D) zero.

    Correct Answer: B

    Solution :

    [b] Comparing the given equation with \[y=x\tan \theta -\frac{\text{g}{{\text{x}}^{2}}}{2{{\text{u}}^{2}}{{\cos }^{2}}\theta },\text{ we get}\]\[\text{tan}\theta \,\,\text{=}\,\sqrt{3}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner