A) 10 t
B) 5 t
C) 3 t
D) 2 t
Correct Answer: A
Solution :
| [a] According to the question, at any instant t, \[x=4{{t}^{2}},\text{ }y=3{{t}^{2}}\] |
| \[\therefore {{\text{v}}_{x}}=\frac{dx}{dt}=\frac{d}{dt}\left( 4{{t}^{2}} \right)=8t\] |
| \[\text{and }{{\text{v}}_{y}}=\frac{dy}{dt}=\frac{d}{dt}\left( 3{{t}^{2}} \right)=6t\]\[\text{and }{{\text{v}}_{y}}=\frac{dy}{dt}=\frac{d}{dt}\left( 3{{t}^{2}} \right)=6t\] |
| The speed of the particle at instant t.. |
| \[\text{v}\,\text{=}\,\sqrt{\text{v}_{\text{x}}^{\text{2}}\text{+v}_{\text{y}}^{\text{2}}}\,\text{=}\,\sqrt{{{\left( \text{8t} \right)}^{\text{2}}}\text{+}{{\left( \text{6t} \right)}^{\text{2}}}}\text{=10}\,\text{t}\] |
You need to login to perform this action.
You will be redirected in
3 sec
