A) \[0.02\times {{10}^{5}}N/{{m}^{2}}\]
B) \[0.02\times {{10}^{7}}N/{{m}^{2}}\]
C) \[50\times {{10}^{7}}N/{{m}^{2}}\]
D) \[50\times {{10}^{9}}N/{{m}^{2}}\]
Correct Answer: D
Solution :
[d] \[B=-\frac{\Delta P}{\Delta V/V}=\frac{100\times {{10}^{5}}}{(0.02/100)}\] \[=50\times {{10}^{9}}N/{{m}^{2}}s\]
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