question_answer

A metallic wire of length 2.0 m is elongated by 2.0 mm. Area of cross-section of the wire is 4.0 mm2. The elastic potential energy stored in the wire in elongated condition is [young's modulus of the metallic wire is \[=2\times {{10}^{11}}N/{{m}^{2}}\]]

A) 8.23

B) 0.83  

C) 6.23

D) 0.63