A) \[5\times {{10}^{-3}}N/m\]
B) \[5\times {{10}^{-2}}N/m\]
C) \[5N/m\]
D) \[50N/m\]
Correct Answer: B
Solution :
[b] \[W=mg=\rho (\pi {{r}^{2}}h)g\] \[or\,\,\,W\simeq \rho (\pi {{r}^{2}})\times \left( \frac{2T}{\rho rg} \right)g\,\,\,\,or\,\,W=2\pi rT\] \[\therefore \,\,\,T=\frac{W}{2\pi r}=\frac{6.28\times {{10}^{4}}}{2\pi \times 2\times {{10}^{-3}}}=5\times {{10}^{-2}}N/m\]
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