A) 1.1m
B) 0.15m
C) 0.20m
D) 0.25m
Correct Answer: A
Solution :
[a] Let depth of bubble below the liquid surface, \[h=?\] As we know, \[{{\rho }_{Excess}}=h\rho g+\frac{2s}{r}\] \[\Rightarrow \,\,1100=h\times {{10}^{3}}\times 9.8+\frac{2\times 6\times {{10}^{-2}}}{{{10}^{-3}}}\] \[\Rightarrow \,\,\,1100=9800h+120\Rightarrow 9800h=1100-120\] \[\Rightarrow \,\,h=\frac{980}{9800}=0.1m\]
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