JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Self Evaluation Test - Mechanical Properties of Fluids

  • question_answer
    The lower end of a capillary tube of radius 2.00mm is dipped 10.00cm below the surface of water in a beaker. Calculate the pressure within a bubble blown at its end in water, in excess of atmospheric pressure. [Surface tension of water\[72\times {{10}^{-3}}N/m\]]

    A) \[718N{{m}^{-2}}\]

    B) \[912N{{m}^{-2}}\]

    C) \[1160N{{m}^{-2}}\]

    D) \[1052N{{m}^{-2}}\]

    Correct Answer: D

    Solution :

    [d] The pressure at a point just outside the bubble \[{{p}_{0}}={{P}_{atm}}+h\rho g={{P}_{atm}}+10\times {{10}^{-2}}\times {{10}^{3}}\times 9.8\] \[={{P}_{atm}}+980N{{m}^{-2}}\] Now excess pressure within the bubble compared to a point just outside \[=\frac{2T}{R}=\frac{2\times 72\times {{10}^{-3}}}{2\times {{10}^{-3}}}72N{{m}^{-2}}\] \[\therefore \] Inside pressure = excess pressure + outside pressure \[={{P}_{atm}}+980+72={{P}_{atm}}+1052N{{m}^{-2}}\] \[\therefore \] Pressure within the bubble in excess of atmospheric pressure\[=1052N{{m}^{-2}}\].


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