A) \[\sqrt{\frac{3T}{g(3\rho -\sigma )}}\]
B) \[\sqrt{\frac{6T}{g(2\rho -\sigma )}}\]
C) \[\sqrt{\frac{3T}{g(2\rho -\sigma )}}\]
D) \[\sqrt{\frac{3T}{g(4\rho -3\sigma )}}\]
Correct Answer: C
Solution :
[c] Balancing the forces acting on the drop, we get \[\frac{4}{3}\pi {{r}^{3}}\rho g=2\pi rT+\frac{1}{2}.\frac{4}{3}\pi {{r}^{3}}\sigma \Rightarrow r=\sqrt{\frac{3T}{(2\rho -\sigma )g}}\]
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