A) \[{{10}^{-1}}N/{{m}^{2}}\]
B) \[{{10}^{-2}}N/{{m}^{2}}\]
C) \[{{10}^{-3}}N/{{m}^{2}}\]
D) \[{{10}^{-4}}N/{{m}^{2}}\]
Correct Answer: B
Solution :
[b] \[\eta ={{10}^{-2}}\,poise\] \[v=18km/h=\frac{18000}{3600}=5m/s\] \[l=5m\] Strain rate\[=\frac{v}{l}\] \[Coefficient\,of\,vis\cos ity,\eta =\frac{shearing\,stress}{strain\,rate}\] \[\therefore \,\,\,Shearing\,stress=\eta \times strain\,rate\] \[={{10}^{-2}}\times \frac{5}{5}={{10}^{-2}}N{{m}^{-2}}\]
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