A) \[1.6\times {{10}^{-5}}cm{{s}^{-1}}\]
B) \[6.25\times {{10}^{-4}}cm{{s}^{-1}}\]
C) \[6.45\times {{10}^{-4}}cm{{s}^{-1}}\]
D) \[1.5\times {{10}^{-5}}cm{{s}^{-1}}\]
Correct Answer: B
Solution :
[b] \[v\propto \frac{\rho -{{\rho }_{0}}}{\eta }\] \[\therefore \,\,\,\frac{{{v}_{2}}}{{{v}_{1}}}=\frac{\rho -{{\rho }_{02}}}{\rho -{{\rho }_{01}}}\times \frac{{{\eta }_{1}}}{{{\eta }_{2}}}=\frac{7.8-1.2}{7.8-1}\times \frac{8.5\times {{10}^{-4}}\times 10}{13.2}\] \[=6.25\times {{10}^{-4}}cm{{s}^{-1}}\]
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