A) \[\sqrt{2}\]
B) \[\frac{1}{\sqrt{2}}\]
C) \[\sqrt{2}-1\]
D) \[\frac{1}{\sqrt{2}-1}\]
Correct Answer: C
Solution :
[c] \[t=k(\sqrt{{{h}_{1}}}-\sqrt{{{h}_{2}}})\] \[\therefore \,\,\,{{t}_{1}}=k(\sqrt{h}-\sqrt{h/2})\]and \[{{t}_{2}}=k(\sqrt{h/2}-0)\] \[\therefore \,\,\frac{{{t}_{1}}}{{{t}_{2}}}=\sqrt{2}-1\]
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