JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Self Evaluation Test - Mechanical Properties of Fluids

  • question_answer
    Air of density \[1.2kg{{m}^{-3}}\] is blowing across the horizontal wings of an aero plane in such a way that its speeds above and below the wings are \[150m{{s}^{-1}}\] and\[100m{{s}^{-1}}\], respectively. The pressure difference between the upper and lower sides of the wings, is

    A) \[60N{{m}^{-2}}\]

    B) \[180\,N{{m}^{-2}}\]

    C) \[7500N{{m}^{-2}}\]

    D) \[12500N{{m}^{-2}}\]

    Correct Answer: C

    Solution :

    [c] Pressure difference \[{{P}_{2}}-{{P}_{1}}=\frac{1}{2}\rho (v_{2}^{2}-v_{1}^{2})\] \[=\frac{1}{2}\times 1.2\left( {{(150)}^{2}}-{{(100)}^{2}} \right)=7500N{{m}^{-2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner