A) \[1000s\]
B) \[2000s\]
C) \[1500s\]
D) \[500s\]
Correct Answer: A
Solution :
[a] Let x be the height of the water level from The hole \[v=\sqrt{2gx}=\frac{\ell }{t}=\frac{1}{t}\] ...(i) For vertical motion \[x=\frac{1}{2}g{{t}^{2}}\] ?(ii) Now solving (i) & (ii) we get \[\Rightarrow \,x=0.25m\] (i.e. level goes down from 0.81m to 0.25m.) Using equation of continuity \[\sqrt{5.\,}\frac{dx}{dt}=\sqrt{2gx.}4\times {{10}^{-4}}\]On solving \[t=1000s\]
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