JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Self Evaluation Test - Mechanical Properties of Fluids

  • question_answer
    A balloon of volume F, contains a gas whose density is to that of the air at the earth's surface as 1:15. If the envelope of the balloon be of weight w but of negligible volume, find the acceleration with which it will begin to ascend.

    A) \[\left( \frac{7Vg\sigma -w}{Vg\sigma +w} \right)\times g\]

    B) \[\left( \frac{2Vg\sigma -w}{Vg\sigma +w} \right)\times g\]

    C) \[\left( \frac{14Vg\sigma -w}{Vg\sigma +w} \right)\times g\]

    D) \[\left( \frac{14Vg\sigma +w}{Vg\sigma -w} \right)\times g\]

    Correct Answer: C

    Solution :

    [c] Let a be the density of the gas, then that of the air is \[15\sigma \]. Then the weight of the balloon = weight of the gas + weight of the envelope \[=Vg\sigma +w\] If f be the required acceleration of the balloon acting vertically upward and then from "mass acceleration=forces acting in the sense of acceleration" we get \[\frac{(Vg\sigma +w)}{g}\times a\]force of buoyance - wt. of the balloon with gas\[=V15\sigma g-(Vg\sigma \times w)\] \[or\,\,a=\left( \frac{14Vg\sigma -w}{Vg\sigma +w} \right)\times g\]


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