A) \[\frac{5}{4}d\]
B) \[\frac{d}{4}\]
C) \[4d\]
D) \[\frac{d}{5}\]
Correct Answer: A
Solution :
[a] Weight of cylinder = Upthrust due to upper liquid + Upthrust due to lower liquid. \[D\left( \frac{A}{5}\times L\times g \right)=d\left( \frac{A}{5} \right)\left( \frac{3}{4}L \right)g+2d\left( \frac{A}{5} \right)\left( \frac{L}{4} \right)\times g\] \[\therefore \,\,D=\frac{5d}{4}\]
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