A) \[\left( \frac{\eta -1}{\eta } \right)mg\]
B) \[\eta mg\]
C) \[\frac{mg}{\eta -1}\]
D) \[(\eta -1)mg\]
Correct Answer: D
Solution :
[d] \[T+mg={{F}_{b}}\] \[\therefore \,\,T={{F}_{b}}-mg\] \[=V{{\rho }_{w}}g-mg\] \[=\frac{m}{({{\rho }_{w}}/\eta )}{{\rho }_{w}}g-mg\] \[=(\eta -1)mg.\]You need to login to perform this action.
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