A) B
B) A
C) O
D) I
Correct Answer: C
Solution :
[c] \[AB=\left[ \begin{matrix} 0 & c & -b \\ -c & 0 & a \\ b & -a & 0 \\ \end{matrix} \right]\left[ \begin{matrix} {{a}^{2}} & ab & ac \\ ab & {{b}^{2}} & bc \\ ac & bc & {{c}^{2}} \\ \end{matrix} \right]\] \[AB=\left[ \begin{matrix} abc-abc & {{b}^{2}}c-{{b}^{2}}c & b{{c}^{2}}-b{{c}^{2}} \\ -{{a}^{2}}c+{{a}^{2}}c & -abc+abc & -ac+ac \\ {{a}^{2}}b-{{a}^{2}}b & a{{b}^{2}}-a{{b}^{2}} & abc-abc \\ \end{matrix} \right]\] \[=\left[ \begin{matrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \\ \end{matrix} \right]=O\]
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