A) 2AB
B) 2BA
C) A+B
D) AB
Correct Answer: C
Solution :
[c] We have, \[{{A}^{2}}+{{B}^{2}}=AA+BB\] \[=A(BA)+B(AB)\] \[(\therefore AB=B\,\,and\,\,BA+A)\] \[=(AB)A+(BA)B\] \[=BA+AB=A+B\,\,\,\,\,\,\,(\therefore \,AB=B\,\,and\,\,BA=A)\]You need to login to perform this action.
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