A) 4.48 T
B) 2.48 T
C) 5.48 T
D) 3.12T
Correct Answer: A
Solution :
[a] Where u is the permeability of the core and \[{{\mu }_{r}}\] is the relative permeability Now, \[{{\mu }_{0}}=4\pi \times {{10}^{-7}}\,TM{{A}^{-1}}\], \[{{\mu }_{r}}=800\] and \[n=\frac{N}{2\pi r}=\frac{3500}{2\pi r}=\frac{3500}{2\pi \times 0.15\,}{{m}^{-1}}\] \[B=\mu \,n\,I={{\mu }_{0}}{{\mu }_{r}}\,n\,I\] \[\therefore \,\,\,\,\,B=\frac{(4\pi \times {{10}^{-7}})\times 800\times 3500\times 1.2}{(2\pi \times 0.15)}=4.48\,T\]
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