JEE Main & Advanced Physics Magnetism Question Bank Self Evaluation Test - Magnetism and Matter

  • question_answer
    A dip circle is so set that its needle moves freely in the magnetic meridian. In this position, the angle of dip is \[40{}^\circ \]. Now the dip circle is rotated so that the plane in which the needle moves makes an angle of \[30{}^\circ \] with the magnetic meridian. In this position, the needle will dip by an angle

    A) \[{{40}^{o}}\]

    B) \[30{}^\circ \]

    C) more than \[40{}^\circ \]

    D) less than \[{{40}^{o}}\]

    Correct Answer: D

    Solution :

    [d] \[{{\delta }_{1}}={{40}^{o}}\], \[{{\delta }_{2}}={{30}^{o}}\]\[\delta =?\] \[\cot \,\delta =\sqrt{{{\cot }^{2}}{{\delta }_{1}}+{{\cot }^{2}}{{\delta }_{2}}}\] \[=\sqrt{{{\cot }^{2}}{{40}^{o}}+{{\cot }^{2}}{{30}^{o}}}\] \[\cot \,\delta =\sqrt{{{1.19}^{2}}+3}=2.1\] \[\therefore \,\,\,\,\delta ={{25}^{o}}\]   i.e.   \[\delta <{{40}^{o}}\].


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