2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Magnetism

JEE Main & Advanced Physics Magnetism Question Bank Self Evaluation Test - Magnetism and Matter

  • question_answer
    A dip needle lies initially in the magnetic meridian when it shows an angle of dip \[\theta \] at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip\[\theta \]. Then \[\frac{\tan \,\theta '}{\tan \,\theta }\]is

    A) \[\frac{1}{\cos \,x}\]

    B) \[\frac{1}{\sin \,x}\]

    C) \[\frac{1}{\tan \,x}\]

    D) \[\cos \,x\]

    Correct Answer: A

    Solution :

    [a] \[\tan \,\theta =\frac{V}{H}\], \[\tan \,{{\theta }^{'}}=\frac{V}{H\,\cos \,x}\];  \[\frac{\tan {{\theta }^{'}}}{\tan \,\theta }=\frac{1}{\cos \,x}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner