A) \[{{10}^{23}}\,A\,m\]
B) \[{{10}^{20}}\,A\,{{m}^{2}}\]
C) \[{{10}^{16}}\,A\,{{m}^{2}}\]
D) \[{{10}^{10}}\,A\,{{m}^{2}}\]
Correct Answer: A
Solution :
[a] Given, \[B=4\times {{10}^{-5}}\,T\] \[{{R}_{E}}=6.4\times {{10}^{6}}m\] Dipole moment of the earth M=? \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{M}{{{d}^{3}}}\] \[4\times {{10}^{-5}}=\frac{4\pi \times {{10}^{-7}}\times M}{4\pi \times {{(6.4\times {{10}^{6}})}^{3}}}\] \[\therefore \,\,\,\,\,\,M\cong {{10}^{23}}\,A{{m}^{2}}\]
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