A) \[5\times {{10}^{-7}}\,T\]
B) \[\sqrt{5}\times {{10}^{-7}}\,T\]
C) \[{{10}^{-7}}\,T\]
D) None of these
Correct Answer: B
Solution :
[b] \[{{B}_{1}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{2M}{{{r}^{3}}}={{10}^{-7}}\times \frac{2\times 1}{{{1}^{3}}}=2\times {{10}^{-7}}\,T\] and \[{{B}_{2}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{M}{{{r}^{3}}}={{10}^{-7}}\times \frac{1}{{{1}^{3}}}={{10}^{-7}}\,T\] Now, \[B=\sqrt{B_{1}^{2}+B_{2}^{2}}=\sqrt{5}\times {{10}^{-7}}\,T\]
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