JEE Main & Advanced Mathematics Differentiation Question Bank Self Evaluation Test - Limits and Derivatives

  • question_answer
    If \[f(x)=\underset{n\,\to \,\infty }{\mathop{\lim }}\,n({{x}^{1/n}}-1),\] then for \[x>0,\,\,y>0,\]\[f(xy)\] is equal to

    A) \[f(x)f(y)\]

    B) \[f(x)+f(y)\]

    C) \[f(x)-f(y)\]

    D) None of these

    Correct Answer: B

    Solution :

    [b] \[f(x)=\underset{n\to \infty }{\mathop{\lim }}\,n({{x}^{1/n}}-1)=\underset{n\to \infty }{\mathop{\lim }}\,\frac{{{x}^{1/n}}-1}{1/n}\] \[=\underset{m\to 0}{\mathop{\lim }}\,\frac{{{x}^{m}}-1}{m}=Inx\,\left( where\,\,\frac{1}{n}\,\,is\text{ }replaced\text{ }by\text{ }m \right)\] or \[f(xy)=ln(xy)=ln\,x+ln\,y=f(x)+f(y)\]


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