A) \[\frac{a-b}{2}\]
B) \[\frac{a-b}{4}\]
C) \[=-\left( \frac{a+b}{2} \right)\]
D) \[\frac{a+b}{4}\]
Correct Answer: C
Solution :
[c] Area of \[\Delta PQR=A\] \[=\frac{-1}{2}[x(b-0)+0(0-y)+a(y-b)]\] \[=\frac{-1}{2}(bx+ax-ab)\] \[\therefore \frac{dA}{dx}=\frac{-1}{2}(a+b)\]You need to login to perform this action.
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