JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    Three blocks A, B and C of masses 4 kg, 2 kg and 1 kg respectively, are in contact on a motionless surface, as shown. If a force of 14 N is applied on the 4 kg block then the contact force between A

    A) 6 N

    B) 8 N

    C) 18 N

    D) 2 N

    Correct Answer: A

    Solution :

    [a] Acceleration of system \[a=\frac{{{F}_{net}}}{{{M}_{total}}}\] \[=\frac{14}{4+2+1}=\frac{14}{7}=2\text{ m/}{{\text{s}}^{2}}\] The contact force between A and B \[=\left( {{m}_{B}}+{{m}_{C}} \right)\times a=\left( 2+1 \right)\times 2=6\text{ N}\]


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