2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Kinetic Theory of Gases

JEE Main & Advanced Physics Kinetic Theory of Gases Question Bank Self Evaluation Test - Kinetic Theory

  • question_answer
    The equation of state of a gas is given by \[\left( P+\frac{a{{T}^{2}}}{V} \right){{V}^{c}}=\left( RT+b \right)\]where a, b, c and R  are constants. The isotherms can be represented \[P=A{{V}^{m}}-B{{V}^{n}},\] where A and 5 depend only on temperature and

    A) \[m=-c\text{ and }n=-1\]

    B) \[m=c\text{ and }n=-1\]

    C) \[m=-c\text{ and }n=1\]

    D) \[m=c\text{ and }n=-1\]

    Correct Answer: A

    Solution :

    [a] \[\left( P+\frac{a{{T}^{2}}}{V} \right){{V}^{c}}=\left( RT+b \right)\] \[\Rightarrow P=(RT+b){{V}^{-c}}-(a{{T}^{2}}){{V}^{-1}}\]  On comparing with equation, \[P=A{{V}^{m}}-B{{V}^{n}},m=-c\text{ and }n=-1.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner