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JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Self Evaluation Test - Introduction to Three Dimensional Geometry

  • question_answer
    The co-ordinates of the point in which the line joining the points (3, 5, -7) and (-2, 1, 8) is intersected by the plane yz are given by

    A) \[\left( 0,\,\,\frac{13}{5},\,\,2 \right)\]

    B) \[\left( 0,-\frac{13}{5},-2 \right)\]

    C) \[\left( 0,-\frac{13}{5},\frac{2}{5} \right)\]

    D) \[\left( 0,\,\,\frac{13}{5},\,\,\frac{2}{5} \right)\]

    Correct Answer: A

    Solution :

    [a] Ratio \[=-\left( \frac{3}{-2} \right)=\frac{3}{2}\] \[\therefore \]      Required co-ordinates of the points are, \[\left[ \frac{6-6}{5},\frac{10+3}{5},\frac{-14+24}{5} \right]=\left( 0,\,\,\frac{13}{5},\,\,2 \right).\]


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