A) Internally in the ratio 2:3
B) Externally in the ratio 2:3
C) Internally in the ratio 3:2
D) Externally in the ratio 3:2
Correct Answer: D
Solution :
[d] Suppose xy-plane divides the line joining the given points in the ration \[\lambda :1\]. The coordinate of the point of division are \[\left( \frac{2\lambda -1}{\lambda +1},\frac{-5\lambda +3}{\lambda +1},\frac{6\lambda +4}{\lambda +1} \right)\]. This point lies on xy-plane. \[\frac{6\lambda +4}{\lambda +1}=0\Rightarrow \lambda =-\frac{3}{2}\] Hence, xy-plane divides externally in the ratio 3 : 2.
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