A) 1:3
B) 3:1
C) -1:3
D) None of these
Correct Answer: B
Solution :
[b] Let A(1, -2, 3) and B (4, 2, -1). Let the plane XOY meet the line AB in the point C such that C divides AB in the ratio k : 1, then \[C\equiv \left( \frac{4k+1}{k+1},\frac{2k-2}{k+1},\frac{-k+3}{k+1} \right)\]. Since C lies on the the plane XOY i.e. the plane z=0, therefore, \[\frac{-k+3}{k+1}=0\Rightarrow k=3.\]
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