A) \[\pi -x\]
B) \[x-\pi \]
C) \[\pi /2-x\]
D) x
Correct Answer: D
Solution :
[d] \[\int{{{\cot }^{4}}xdx=\int{{{\cot }^{2}}x.\left( \cos e{{c}^{2}}x-1 \right)dx}}\] \[=\int{{{\cot }^{2}}x\cos e{{c}^{2}}xdx-\int{(\cos e{{c}^{2}}x-1)dx}}\] \[=-\frac{1}{3}{{\cot }^{3}}x+\cot x+x+c\] \[\therefore \phi (x)=-\frac{1}{3}{{\cot }^{3}}x+\cot x+x+c+\frac{1}{3}\] \[{{\cot }^{3}}x-\cot x\] \[=x+c\] \[\therefore \phi \left( \frac{\pi }{2} \right)=\frac{\pi }{2}+c,\therefore c=0,\therefore \phi (x)=x\]
You need to login to perform this action.
You will be redirected in
3 sec
