A) 10 vol solution
B) 20 vol solution
C) 34 vol solution
D) 32 vol solution
Correct Answer: A
Solution :
[a] \[N=\frac{{{W}_{2}}\times 1000}{E.{{W}_{2}}\times VmL}\] \[=\frac{34\times 1000}{17\times 1120}=\frac{200}{12}\] 1 N of \[{{H}_{2}}{{O}_{2}}=5.6\] vol strength \[\frac{200}{12}N\,of\,{{H}_{2}}{{O}_{2}}=5.6\times \frac{200}{12}=10\] vol strengthYou need to login to perform this action.
You will be redirected in
3 sec