A) water
B) hydrogen peroxide
C) dioxygen
D) phosphine
Correct Answer: B
Solution :
[b] \[\underset{\begin{smallmatrix} Barium \\ peroxide \end{smallmatrix}}{\mathop{3Ba{{O}_{2}}}}\,+\underset{\begin{smallmatrix} Phosphoric \\ acid \end{smallmatrix}}{\mathop{2{{H}_{3}}P{{O}_{4}}}}\,\to \underset{\begin{smallmatrix} Barium \\ phosphate \end{smallmatrix}}{\mathop{B{{a}_{3}}}}\,{{(P{{O}_{4}})}_{2}}+\underset{\begin{smallmatrix} Hydrogen \\ peroxide \end{smallmatrix}}{\mathop{3{{H}_{2}}{{O}_{2}}}}\,\]You need to login to perform this action.
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