A) \[\frac{100}{3}mL\]
B) \[\frac{500}{3}mL\]
C) \[\frac{300}{5}mL\]
D) None
Correct Answer: B
Solution :
[b] \[Mn{{O}_{4}}^{-}+5{{e}^{-}}\to M{{n}^{2+}}\] (acidic) \[Mn{{O}_{4}}^{-}+3{{e}^{-}}\to Mn{{O}_{2}}\] (basic) \[100\,mL\,{{H}_{2}}{{O}_{2}}\equiv 100\times 5N\] \[Mn{{O}_{4}}^{-}\equiv V\times 3N\,Mn{{O}_{2}}\] \[N=\frac{500}{3}mL\]You need to login to perform this action.
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