A) \[Mg+\frac{1}{2}{{O}_{2}}\to MgO~\]
B) \[2Ag+\frac{1}{2}{{O}_{2}}\to A{{g}_{2}}O\]
C) \[C+\frac{1}{2}{{O}_{2~}}\to CO\]
D) \[CO+\frac{1}{2}{{O}_{2~}}\to C{{O}_{2}}\]
Correct Answer: C
Solution :
[c] \[C(s)+\frac{1}{2}{{O}_{2}}(g)\to CO(g);\Delta S\] increases. Hence, as the temperature increases, \[T\Delta S\] increases and hence \[\Delta G\left( \Delta H-T\Delta S \right)\] decreases. In other words, the slope of the 1 curve for formation of CO decreases. However, for all other oxides, it increases.
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