A) Ga and in
B) Zr and Ti
C) Ag and Au
D) Ni and Fe
Correct Answer: B
Solution :
[b] Zr and Ti are purified by van Arkel method. \[Zr(s)+2{{I}_{2}}(g)\xrightarrow{870K}Zr{{I}_{4}}(g)\] \[Zr{{I}_{4}}(g)\xrightarrow[Tugsten\,filament]{2075K}Zr(s)+2{{I}_{2}}(g)\] \[Ti(s)+2{{I}_{2}}(s)\xrightarrow{523K}Ti{{I}_{4}}(g)\] \[Ti{{I}_{4}}\xrightarrow{1700K}\underset{Pure\text{ }titanium}{\mathop{Ti(s)}}\,+2{{I}_{2}}(g)\]
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