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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    What is the percentage hydrolysis of NaCN in N/80 solution when the dissociation constant for \[HCN\] is \[1.3\times {{10}^{-9}}\]and \[{{K}_{w}}=1.0\times {{10}^{-14}}\]

    A) 2.48                 

    B) 5.26 

    C) 8.2                   

    D) 9.6

    Correct Answer: A

    Solution :

    [a] \[\alpha =\sqrt{\frac{{{K}_{w}}}{{{K}_{a}}\times c}}\sqrt{\frac{{{10}^{-14}}}{1.3\times {{10}^{-9}}\times \frac{1}{80}}}=2.48%.\] %


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