JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electrostatic Potential and Capacitance

  • question_answer
    A series combination of \[{{n}_{1}}\] capacitors, each of capacity \[{{C}_{1}}\] is charged by source of potential difference 4 V. When another parallel combination of \[{{n}_{2}}\]capacitors each of capacity \[{{C}_{2}}\]is charged by a source of potential deference V, it has the same total energy stored in it as the first combination has. The value of \[{{C}_{2}}\]in terms of \[{{C}_{1}}\]is then

    A) \[16\frac{{{n}_{2}}}{{{n}_{1}}}{{C}_{1}}\]

    B) \[\frac{2{{C}_{1}}}{{{n}_{1}}{{n}_{2}}}\]

    C) \[2\frac{{{n}_{1}}}{{{n}_{2}}}{{C}_{1}}\]

    D)        \[\frac{16{{C}_{1}}}{{{n}_{1}}{{n}_{2}}}\]

    Correct Answer: D


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