question_answer

A network of six identical capacitors, each of value C is made as shown in the figure. Equivalent capacitance between points A and B is

A) C/4      

B) 3C/4

C) 4C/3    

D) 3C

Correct Answer: C

Solution :

[c] The network is equivalent to Therefore equivalent capacitance \[\text{=}\left[ \text{2C series C} \right]\text{//}\left[ \text{C series 2C} \right]\]\[=2\left( \frac{2C\times C}{2C+C} \right)=\frac{4C}{3}\]